Log2 (7x 1)=1+ log2(3x-5)

Question

Log2 (7x 1)=1+ log2(3x-5)

Answer 1

Там в 1 скобке какой знак между 7х и 1

Comments

плюс

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log2(7x+1)=log2от2+log2(3x-5)...7x+1=2(3x-5)...7x+1=6x-10...x=-11