Решение tg(2x-п/3)=1
Tg(2x-π/3)=1 2x-π/3=arctg1+πk, k∈Z 2x-π/3=π/4+πk, k∈Z 2x=π/3+π/4+πk, k∈Z 2x=7π/12+πk, k∈Z x=7π/24+πk/2, k∈Z ответ: x=7π/24+πk/2, k∈Z