Решите систему, прошу, срочно! {Log6 x + log6y=2 x-y=-5

Решите задачу:

$\left \{ {{log_6x+log_6y=2} \atop {x-y=-5}} \right. \; \left \{ {{log_6(xy)=2} \atop {x-y=-5}} \right. \; \left \{ {{xy=6^2,\; x\ \textgreater \ 0,\; y\ \textgreater \ 0} \atop {x-y=-5}} \right. \; \left \{ {{x(x+5)=36} \atop {y=x+5}} \right. \\\\x^2+5x-36=0\; ,\; \; D=169,\\\\x_1=\frac{-5-13}{2}=-9\ \textless \ 0\; \; ne \; podxodit\\\\x_2=4\; ,\; \; \; y_2=4+5=9\\\\Otvet:\; \; (4,9).$