Sin5x-√3cos5x=2 помогите
2(sin5x*1/2-cos5x*√3/2)=2 sin5xcosπ/3-cos5xsinπ/3=1 sin(5x-π/3)=1 5x-π/3=π/2+2πn,n∈z 5x=5π/6+2πn,n∈z x=π/6+2πn/5,n∈z