(sqrt3-sqrt2)*qwrt72/3(2sqwrt6-sqrt16)(^3sqrt64+1)

$(\sqrt3-\sqrt2)*\frac{\sqrt{72}}{3(2\sqrt6-\sqrt16)}(\sqrt[3]{64}+1)=$

$=(\sqrt3-\sqrt2)*\frac{\sqrt{36*2}}{3(2\sqrt6-4)}(4+1)=(\sqrt3-\sqrt2)*\frac{\sqrt{36}*\sqrt2}{6(\sqrt6-2)}}*5=$

$(\sqrt3-\sqrt2)*\frac{\sqrt{36}*\sqrt2}{6(\sqrt6-2)}}*5=(\sqrt3-\sqrt2)*\frac{6*\sqrt2}{6(\sqrt3*\sqrt2-(\sqrt2)^2)}}*5=$

$=(\sqrt3-\sqrt2)*\frac{\sqrt2}{\sqrt2(\sqrt3-\sqrt2)}}*5=5$

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