1)3[x+3]-[5x-2]=3 2) 6x-12=x^2[x-2] 3) x^4-13x^2+36=0

Question

1)3[x+3]-[5x-2]=3

2) 6x-12=x^2[x-2]

3) x^4-13x^2+36=0

Answer 1

1)3(x+3)-(5x-2)=3

3х+9-5х+2=3

3х-5х=3=3-2-9

-2х=-8

х=-8:(-2)

х=4

проверка:

  3(4+3)-(5*4-2)=3 

 

 

 

Answer 2

1) 3(x+3)-(5x-2)=3

3x+9-5x-2=3

3x-5x-2+9=3

-2x+7=3 |*(-1)

2x-7=3

2x-7-3=0

2x=-10

x=-5