1/2log2_(x + 12)*logx_2 = 1;
1/2log2_(x+12)/log2_x = 1;
logx_(x + 12) = 2;
x^2 = x + 12;
x^2 - x - 12 = 0;
(x - 4)(x + 3) = 0;
x1 = 4; x2 = -3;
По ОДЗ x2 - посторонний.
Ответ: 4.
1 + logx_5*log7_x = log5_35*logx_5;
1 + logx_5/logx_7 = log5_35/log5_x;
1 + log7_5 = logx_35;
log7_35 = logx_35;
x = 7;
Проверяем по ОДЗ;
Ответ: 7.