Решите неравенство. ОЧЕНЬ СРОЧНО! 1) 5^(4x-7)>1 2) (1/4)^x - 3*(1/2)^x+2>0 Заранее...

1) $5^{4x-7}\ \textgreater \ 1;\, 4x-7\ \textgreater \ 0;\,x\ \textgreater \ \frac{7}{4}.$
2) $(\frac{1}{4})^x - 3\cdot (\frac{1}{2})^x+2\ \textgreater \ 0;\, 2\cdot 4^x-3\cdot 2^x+1\ \textgreater \ 0;\,(2^x-1)(2\cdot2^x-1)\ \textgreater \ 0;$
$2^x\in(0; \frac{1}{2})\cup(1;\infty);\, x\in(-\infty; -1)\cup(0;+\infty)$