Решите уравнение Lg(3x-10)=lg(7-2x)

$lg(3x-10)=lg(7-2x)\\-------------\\ \left \{ {{3x-10\ \textgreater \ 0} \atop {7-2x\ \textgreater \ 0}} \right. \\ \left \{ {{3x\ \textgreater \ 10} \atop {-2x\ \textgreater \ -7}} \right. \\ \left \{ {{x\ \textgreater \ \frac{10}{3} } \atop {x\ \textless \ \frac{7}{2} }} \right. \\ x\in(\frac{10}{3};\frac{7}{2} )\\ -------------\\ 3x-10=7-2x\\ 3x+2x=7+10\\ 5x=17\\ x= \frac{17}{5} \\ x=3.4$

Ответ: x=3.4