1) (Х-5)(х+2)=х(5-х) ; 2)(х+2)*=4(х+4)

Question

1) (Х-5)(х+2)=х(5-х) ; 2)(х+2)*=4(х+4)

Answer 1

X^2+2x-5x-10-5x+x^2=0
2x^2+2x-5x-10-5x+x^2=0
2x^2-8x-10=0
x^2-4x-5=0
D=b^2-4ac=(-4)^2-4*(-5)=36
X1=(4-6):2=-1
X2=(4+6):2=5