2 sin x>1 Корень из 2 cosx <1 sin( x-П/6)>=-1/2

Question

2 sin x>1
Корень из 2 cosx <1<br> sin( x-П/6)>=-1/2

Answer 1

2sinx>1
sinx>1/2
π/6+2πnπ/6+2πn
сosx<1/√2<br>arccos(1/√2)+2πnπ/4+2πn
sin(x-π/6)>-1/2
-π/6+2πk-π/6+π/6+2πK2πK