Помогите 1) x-2 1/3=5 2/7 2) z-1 3/4=2 7/12 3) y-10 7/12=3 1/6 заранее спасибо

Решите задачу:

$x-2 \frac{1}{3} =5 \frac{2}{7} \\ \\ x =5 \frac{2}{7} -2 \frac{1}{3} \\ \\ x =5 \frac{2*3}{21} -2 \frac{1*7}{21} \\ \\ x=5 \frac{6}{21} -2 \frac{7}{21} \\ \\ x=4 \frac{27}{21} -2 \frac{7}{21} \\ \\x=2 \frac{20}{21}$

$z - 1 \frac{3}{4} =2 \frac{7}{12} \\ \\ z=2 \frac{7}{12}-1 \frac{3}{4} \\ \\ z=2 \frac{7}{12}-1 \frac{9}{12} \\ \\ z=1 \frac{19}{12} -1 \frac{9}{12} \\ \\ z=\frac{10}{12} \\ \\ z= \frac{5}{6}$

$y-10 \frac{7}{12} =3 \frac{1}{6} \\ \\ y=3 \frac{1}{6}-10 \frac{7}{12} \\ \\ y=3\frac{2}{12}-10 \frac{7}{12} \\ \\ y=2\frac{14}{12}-10\frac{7}{12} \\ \\ y=(-8 \frac{7}{12} )$