3(2х+5)/8-2(5х+7)/3=7( х-15)/4-67/8

Решите задачу:

$\frac{3(2x+5)}{8} - \frac{2(5x+7)}3= \frac{7(x-15)}{4} } -6 \frac{7}{8} \\ \frac{3(2x+5)}{8} - \frac{2(5x+7)}3- \frac{7(x-15)}{4} } =-6 \frac{7}{8} \\ \frac{9(2x+5)}{24} - \frac{16(5x+7)} {24}- \frac{42(x-15)}{24} } =-6 \frac{7}{8} \\ \frac{18x+45}{24} - \frac{80x-112} {24}- \frac{42x+630}{24} } =-6 \frac{7}{8} \\ \frac{-104+563}{24} =-6 \frac{7}{8} \\ -104x+563= -\frac{55}{8} *24 \\ -104x+563=-165 \\ -104x=-165-563 \\ -104x=-728 \\ x=728:104 \\ x=7$