1) 2 log2_ (-3x) = -8 2) Log3_x - log12_x = log144_2

Question

1) 2 log2_ (-3x) = -8
2) Log3_x - log12_x = log144_2

Answer 1

2log₂(-3x)=-8
ОДЗ:
-3x>0, x<0<br>log₂(-3x)²=-8
(-3x)²=2⁻⁸
9x²=1/256
x²=1/(256*9)
x=+-1/48
x₁=-1/48, x₂=1/48. 1/48>0, посторонний корень
ответ: x=-1/48