1. Найдите область опр функции У= 1-х/log3(x^2-9) 2. Запишите в тригонометрической форме...

Решите задачу:

$1)\; \; y=\frac{1-x}{log_3(x^2-9)}\; ,\; \; OOF:\; \; \left \{ {{log_3(x^2-9)\ne 0} \atop {x^2-9\ \textgreater \ 0}} \right. \; \left \{ {{x^2-9\ne 1} \atop {(x-3)(x+3)\ \textgreater \ 0}} \right. \\\\ \left \{ {{x^2\ne 10} \atop {x\in (-\infty ,-3)\cup (3,+\infty )}} \right. \; \left \{ {{x\ne \pm \sqrt{10}} \atop {x\in (-\infty ,-3)\cup (3,+\infty )}} \right. \; \Rightarrow \\\\x\in (-\infty ,-\sqrt{10})\cup (-\sqrt{10},-3)\cup (3,\sqrt{10})\cup (\sqrt{10},+\infty )$

$2)\; \; z=\frac{\sqrt3}{2}-\frac{1}{2}i\\\\|z|=\sqrt{\frac{3}{4}+\frac{1}{4}}=1\; ,\\\\argz=arctg\frac{-1/2}{\sqrt3/2}=-arctg\frac{1}{\sqrt3}=-\frac{\pi}{6}\\\\z=cos(-\frac{\pi}{6})+isin(-\frac{\pi}{6})$