Помогите плиз {logx y=2 {logx-1 (y+23)=3

Question

Помогите плиз
{logx y=2
{logx-1 (y+23)=3

Answer 1

log3(x-2)+log3(x+2)=log3(2x-1)log3(x-2)(x+2)=log3(2x-1)log3(x^{2}-4)=log3(2x-1)x^{2}-4=2x-1x^{2}-2x-3=0x=3,х=-1-1-посторонний кореньОтвет:3