2/3x-4/5=√sin30°+sin 7π/4

Решите задачу:

$\frac{2}{3}x- \frac{4}{5}= \sqrt{sin30}+sin7 \pi /4\\ \frac{2}{3}x- \frac{4}{5}= \sqrt{ \frac{1}{2} }+sin(2 \pi - \pi /4)\\ \frac{2}{3}x- \frac{4}{5}= \frac{1}{ \sqrt{2} }-sin \pi /4\\\frac{2}{3}x- \frac{4}{5}= \frac{1}{ \sqrt{2} }- \frac{ \sqrt{2} }{2}\\ \frac{2}{3}x- \frac{4}{5}= \frac{2-( \sqrt{2})^2 }{2 \sqrt{2} }\\ \frac{2}{3}x- \frac{4}{5}= \frac{2-2}{2 \sqrt{2} }\\ \frac{2}{3}x- \frac{4}{5}= \frac{0}{2 \sqrt{2} }\\ \frac{2}{3}x- \frac{4}{5}=0\\ \frac{2}{3}x= \frac{4}{5}$
$x= \frac{4}{5} : \frac{2}{3}\\x= \frac{4}{5} * \frac{3}{2}\\x= \frac{6}{5}\\x=1,2$