\frac{2a+1}{12}|*24\\\\3(5a-3)>2(2a+1)\\\\15a-9>4a+2\\\\15a-4a>2+9\\\\11a>11|:11\\\\a>1\\\\a\in (1;+\infty)" alt="\frac{5a-3}{8}>\frac{2a+1}{12}|*24\\\\3(5a-3)>2(2a+1)\\\\15a-9>4a+2\\\\15a-4a>2+9\\\\11a>11|:11\\\\a>1\\\\a\in (1;+\infty)" align="absmiddle" class="latex-formula">