Решите выражения : (а-1целая 18/19)-11/38=2, (18 целых 6/7+у)-12целых 2/3=8целых 1/7

Решите задачу:

$(a-1 \frac{18}{19} )- \frac{11}{38}=2$
$(a-1 \frac{18}{19} )=\frac{11}{38}+2$
$a-1 \frac{18}{19}=2\frac{11}{38}$
$a=1 \frac{18}{19}+2\frac{11}{38}$
$a=1 \frac{36}{38}+2\frac{11}{38}$
$a=3 \frac{47}{38}$
$a=4 \frac{9}{38}$

$(18\frac{6}{7}+y)-12\frac{2}{3}=8 \frac{1}{7}$
$18\frac{6}{7}+y=12\frac{2}{3}+8 \frac{1}{7}$
$18\frac{6}{7}+y=12\frac{17}{21}+8 \frac{3}{21}$
$18\frac{6}{7}+y=21\frac{20}{21}$
$y=21\frac{20}{21} -18\frac{6}{7}$
$y=21\frac{20}{21} -18\frac{18}{21}$
$y=3\frac{2}{21}$