НАЙТИ ЗНАЧЕНИЕ ПРОИЗВОДНОЙ ФУНКЦИИ f(X)=1-6∛Х В ТОЧКЕ Х0=8
F'(x) = (1-6∛x)' = 1' - (6∛x)' = 0-6 (x^1/3)' = -6*1/3 x^(1/3-1) = -2x^(-2/3)= = f'(8) =
![\frac{-2}{ \sqrt[3]{x^2} }](https://tex.z-dn.net/?f=+%5Cfrac%7B-2%7D%7B+%5Csqrt%5B3%5D%7Bx%5E2%7D+%7D+ "\frac{-2}{ \sqrt[3]{x^2} }")
![\frac{-2}{ \sqrt[3]{8^2} } = \frac{-2}{ \sqrt[3]{64} } = \frac{-2}{4} = \frac{-1}{2} =-0.5](https://tex.z-dn.net/?f=+%5Cfrac%7B-2%7D%7B+%5Csqrt%5B3%5D%7B8%5E2%7D+%7D+%3D+%5Cfrac%7B-2%7D%7B+%5Csqrt%5B3%5D%7B64%7D+%7D+%3D++%5Cfrac%7B-2%7D%7B4%7D++%3D++%5Cfrac%7B-1%7D%7B2%7D++%3D-0.5 "\frac{-2}{ \sqrt[3]{8^2} } = \frac{-2}{ \sqrt[3]{64} } = \frac{-2}{4} = \frac{-1}{2} =-0.5")