(7 3/16-5 1/4x)+3 3/4=9 1/16 4)

Решите задачу:

$(3 \frac{2}{3} y+ \frac{1}{6} )-3 \frac{7}{12} =1 \frac{1}{6}$
$3 \frac{2}{3} y =1 \frac{1}{6}- \frac{1}{6} +3 \frac{7}{12}$
$3 \frac{2}{3} y =4 \frac{7}{12}$
$\frac{11}{3} y = \frac{55}{12}$
$y = \frac{55}{12}: \frac{11}{3}$
$y = \frac{55}{12}* \frac{3}{11}$
$y = \frac{5}{4}$
$y = 1,25$

$(7 \frac{3}{16} -5 \frac{1}{4} x)+3 \frac{3}{4} =9 \frac{1}{16}$
$-5 \frac{1}{4} x =9 \frac{1}{16} -7 \frac{3}{16}-3 \frac{3}{4}$
$-5 \frac{1}{4} x =9 \frac{1}{16} -7 \frac{3}{16}-3 \frac{12}{16}$
$-5 \frac{1}{4} x =-1 \frac{14}{16}$
$-5 \frac{1}{4} x =-1 \frac{7}{8}$
$\frac{21}{4} x = \frac{15}{8}$
$x = \frac{15}{8} : \frac{21}{4}$
$x = \frac{15}{8}* \frac{4}{21}$
$x = \frac{5}{2}* \frac{1}{7}= \frac{5}{14}$