3sinxcosx-2cos^2x=0 .

Question

3sinxcosx-2cos^2x=0 .

Answer 1

3sinxcosx -2cos²x =0 ;
cosx(3sinx -2cosx) =0 . ⇔[ cosx =0 ; 3sinx -2cosx =0 .⇔[ cosx =0 ; tqx=2/3 .
[ x =π/2+π*n ; x =arctq(2/3) +π*n , n∈Z.

ответ : π/2+ π*n ;  arctq(2/3) +π*n , n∈Z.