(2 1/3-3 3/8) *4 4/5 +2 4/9

Решите задачу:

$=( \frac{2*3*8+1*8}{3*8}- \frac{3*8*3+3*3}{8*3})* \frac{4*5+4}{5} + \frac{2*9+4}{9}= (\frac{48+8}{24}- \frac{72+9}{24})* \frac{24}{5}+ \frac{22}{19}=$
$( \frac{56-81}{24} )* \frac{24}{5}+ \frac{22}{19}= - \frac{25}{24}* \frac{24}{5}+ \frac{22}{19}=-5+ \frac{22}{19}=- \frac{5*19}{19}+ \frac{22}{19}=\frac{-95+22}{19}=$
$- \frac{73}{19} =-3 \frac{16}{19}$