Решите уравнение:

$-\frac{3x}{7}+3(x-\frac{2}{7})+11=-\frac{7x}{2}+3(x+1)$

$-\frac{3x}{7}+3x-\frac{6}{7}+11=-\frac{7x}{2}+3x+3$

$-\frac{3x}{7}-\frac{6}{7}+11=-\frac{7x}{2}+3$

$-\frac{3x}{7}+\frac{7x}{2}=3-11+\frac{6}{7}$

$\frac{49x-6x}{14}=-8+\frac{6}{7}$

$\frac{43x}{14}=-7\frac{1}{7}$

$43x=-\frac{50}{7}*14$

$43x=-50*2$

$x=-100:43$

$x=-2\frac{14}{43}$

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