(x-0.6)(x^2-3x-4)=(4x-2.4)(x+1)^2

Question

(x-0.6)(x^2-3x-4)=(4x-2.4)(x+1)^2

Answer 1

(x-0.6)(x^2-3x-4)=(4x-2.4)(x+1)^2

1)
x^2-3x-4=(x+1)(x-4)
x1+x2 = 3
x1*x2 = -4
x1 = -1
x2 = 4

(x-0.6)(x+1)(x-4) = 4(x-0.6)(x+1)(x+1)          | :(x-0.6)(x+1)

(x-4) = 4(x+1)
x-4 = 4x+4
-4-4 = 4x-x
-8 = 3x
x = -8/3