2х-24/х-9=х помогите решить

$\frac{2x-24}{x-9} =x \\ \frac{2x-24}{x-9} -x=0 \\ \frac{(2x-24)-x(x-9)}{x-9} =0 \\ \frac{2x-24- x^{2} +9x}{x-9} =0 \\ \left \{ {{2x-24- x^{2} +9x=0} \atop {x-9 \neq 0}} \right. \\ \left \{ {{- x^{2} +11x-24=0} \atop {x \neq 9}} \right. \\ \left \{ {{ x^{2} -11x+24=0} \atop {x \neq 9}} \right. \\ \left \{ {{x=8;3} \atop {x \neq 9}} \right. \\ x=8 \\ x=3$
отв:8; 3