Помогите пожалуйста ( 7 и 8 )

Решите задачу:

$\frac{10x}{2x-3}-5x \\ \frac{10x-5x(2x-3)}{2x-3} \\ \frac{10x-10x^2+15x}{2x-3} \\ \frac{5}{1-3} -2,5=-5/2-5/2=-5 \\$

$3-2(x-3)\ \textgreater \ 18-5x \\ 3-2x+6\ \textgreater \ 18-5x \\ -2x+9\ \textgreater \ 18-5x \\ -2x+9+5x-18\ \textgreater \ 0 \\ 3x-9\ \textgreater \ 0 \\ 3x\ \textgreater \ 9 |:3 \\ x\ \textgreater \ 3 \\ (3;\infty) or answer = 4$