Надо упростить значение а,b 248
A. sin(30°-α)-(1/2)*cosα=sin30° *cosα-cos30° *sinα-(1/2)*cosα= =(1/2)*cosα-(√3/2)*sinα-(1/2)*cosα=-(√3/2)*sinα b. sinα-√2*sin(α-45°)=sinα-√2*(sinα*cos45°-cosα*sin45°)= =sinα-√2*(sinα*(√2/2)-cosα*(√2/2))=sinα-sinα+cosα=cosα