Log2(x-2)+log2(x-4)=3

Question

Log2(x-2)+log2(x-4)=3

Answer 1

ОДЗ
x-2>0⇒x>2
x-4>0⇒x>4
x∈(4;∞)
log(2)(x-2)(x-4)=3
(x-2)(x-4)=8
x²-2x-4x+8-8=0
x²-6x=0
x(x-6)=0
x=0∉ОДЗ
х=6
Ответ х=6