Log2(8x-3)-log2 5 =1

Question

Log2(8x-3)-log2 5 =1

Answer 1

Log2 (8x - 3) - log 2 (5) = 1 

ОДЗ
8x - 3> 0 ==> x > 0,375

log2 ((8x - 3)/5) = log2 (2)
(8x - 3)/ 5 = 2 
8x - 3 = 5*2 
8x - 3 =10
8x = 13
x = 13/8  = 1,625 

Ответ:
1,625