\left \{ {{3x+8>0} \atop {3x+8\geq 16}} \right. <=> \left \{ {{3x>-8} \atop {3x\geq 8}} \right. <=> \left \{ {{x>-2\frac{2}{3}} \atop {x\geq 2\frac{2}{3}}} \right." alt="log_2(3x+8) \geq 4 <=> \left \{ {{3x+8>0} \atop {3x+8\geq 16}} \right. <=> \left \{ {{3x>-8} \atop {3x\geq 8}} \right. <=> \left \{ {{x>-2\frac{2}{3}} \atop {x\geq 2\frac{2}{3}}} \right." align="absmiddle" class="latex-formula">
ответ 
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