Решите пожалуйста до 16:00 срочно 1068 срочно с координатами пж

$1 \leq \frac{5}{2} + \frac{x}{2}\ \textless \ 2.5$
1-5/2≤x/2<2.5-5/2 -1.5≤0.5x<0 -3≤x<0 $0\ \textless \ \frac{2x}{5}+ \frac{3}{5}\ \textless \ 1$
0-3/5<2x/5<1-3/5 -0.6<0.4x<0.4 -1.5 $2.15\ \textless \ \frac{3x}{4} - \frac{1}{4} \ \textless \ 2.6$
2.15+1/4<3x/4<2.6+1/4 2.15+0.25<0.75x<2.6+0.25 2.4<0.75x<2.85 2.4/0.753.2-1<3/4x-1/4<2 -1<0.75x-0.25<2 -1+2.5<0.75x<2+2.5 1.5/0.752