(x+2)²-x(3x+1)²+(2x+1)(4x²-2x+1)=42

Question

(x+2)²-x(3x+1)²+(2x+1)(4x²-2x+1)=42

Answer 1

Х^2+4х+4-3х^3-6х^2-х+8х^3+1-42=0

-5х^2+3х+5х^3=37

х (-5х+3+5х^2)=37

х=37
-5х+3+5х^2=37
5х^2-5х-34=0
Д=25+680=705

Comments

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