СРОЧНО!!! Решите пожалуйста. Буду очень благодарен.)

Решите задачу:

$\sqrt{7+\sqrt{3+x}}-4=0\\\sqrt{7+\sqrt{3+x}}=4\\7+\sqrt{3+x}=16\\\sqrt{3+x}=9\\3+x=81\\x=78\\ODZ: 3+x\geq 0, x\geq -3\\ \left \{ {{x=78} \atop {x\geq -3}} \right. , x=78$

$|x+2|-|x-1|=x-1.5\\I) x\ \textless \ -2 =\ \textgreater \ |x-1|=1-x, |x+2|=-x-2\\-x-2+x-1=x-1.5\\-3=x-1.5\\ \left \{ {{x=-1.5} \atop {x\ \textless \ -2}} \right. NoSolutions\\\\II) -2\leq x\ \textless \ 1 =\ \textgreater \ |x-1|=1-x, |x+2|=x+2\\x+2+x-1=x-1.5\\ \left \{ {{x=-2.5} \atop {-2\leq x\ \textless \ 1}} \right. , NoSolutions\\\\III)x\geq 1 =\ \textgreater \ |x-1|=x-1, |x+2|=x+2\\x+2-x+1=x-1.5\\ \left \{ {{x=4.5} \atop {x\geq 1}} \right. , x=4.5$