Решите уравнение прошу!!!!

$\frac{ \frac{5}{7} }{ \frac{6}{7}x+ \frac{3}{7} } - \frac{1}{2} = \frac{1}{6}$
$\frac{ \frac{5}{7} }{ \frac{6}{7}x+ \frac{3}{7} } = \frac{1}{6} +\frac{1}{2}$
$\frac{ \frac{5}{7} }{ \frac{6}{7}x+ \frac{3}{7} } = \frac{1}{6} +\frac{3}{6}$
$\frac{ \frac{5}{7} }{ \frac{6}{7}x+ \frac{3}{7} } = \frac{4}{6}$
$\frac{ \frac{5}{7} }{ \frac{6}{7}x+ \frac{3}{7} } = \frac{2}{3}$
по пропорции
$3* \frac{5}{7} = 2*({ \frac{6}{7}x+ \frac{3}{7} } )$
$\frac{15}{7} = { \frac{12}{7}x+ \frac{6}{7} }$
${ \frac{12}{7}x}= \frac{15}{7} - \frac{6}{7}$
${ \frac{12}{7}x}= \frac{9}{7}$
$x= \frac{9}{7} : { \frac{12}{7}}$
$x= \frac{9}{7} * { \frac{7}{12}}$
$x= \frac{3}{4}$