Log0,2(x-10) - log0,2(x+2)>=-1
ОДЗ:
{x-10>0; x>10
{x+2>0; x>-2
x e (10;+беск.)
log0,2[(x-10)/(x+2)] >=log0,2(5)
(x-10)/(x+2) <=5<br>(x-10)/(x+2) - 5<=0<br>[(x-10)-5(x+2)]/(x+2)<=0<br>(x-10-5x-10)/(x+2)<=0<br>(-4x-20)/(x+2)<=0<br>(4x+20)/(x+2)>=0
[4(x+5)]/(x+2)>=0
______+______[-5]_______-____(-2)_____+_______
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С учетом ОДЗ ответ:(10; +беск.)