Помогите решить, пожалуйста.
P =AB+BC+AC = 1.6AC + 1.6AC + AC = 4.2AC 4.2AC = 21 AC = 5 AB = BC = 5*1.6 = 8 A=C => AB = BC P = AB+BC+AC = 0.8AC+0.8AC+AC = 2.6AC 2.6AC = 7.8 AC = 3 AB = BC = 0.8AC = 2.4
1) Допустим AC = x, AB = 1.6 x, BC = 1.6x P = 21, P = AC+AB+BC = 4.2x. 4.2x=21, x=5, AC = 5, AB = BC = 8 2) AC = X, AB = 0.8X = BC (равнобедренный треугольник). P = 7.8. 7.8 = 2.6X, X = 3. AC = 3, AB = BC = 2.4