0\\x-2>0\\log_3(2x+8)\geq log_3(x-2) \end{cases} " alt="\begin{cases} 2x+8>0\\x-2>0\\log_3(2x+8)\geq log_3(x-2) \end{cases} " align="absmiddle" class="latex-formula">
-8\\x>2\\2x+8\geq x-2 \end{cases}" alt="\begin{cases} 2x>-8\\x>2\\2x+8\geq x-2 \end{cases}" align="absmiddle" class="latex-formula">
-4\\x>2\\x\geq -10 \end{cases} " alt="\begin{cases} x>-4\\x>2\\x\geq -10 \end{cases} " align="absmiddle" class="latex-formula">
Ответ х>2
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