Помогите найти производную
1)f⁾(x)=4sin2xcos2x = 2sin4x f(π/16)= 2sinπ/4 = 2*√2/2 = √2 2)f⁾(x) = -4sin2xcos2x = -2sin4x f(π/16) = -2*√2/2 = -√2 3)f⁾(x) = 6tg3x*1/cos²3x f⁾(π/12) = 6tgπ/4 *4/2 = 12 6) 2tgx*1/cos²x + 2ctg*1/sin²x f⁾(π/4) = 2*1*4/2+2*1*4/2 = 4+4=8