0 \\ x+5>0 \\ x\in(-5;\ \frac{1}{3}) \\ \\ \frac{1-3x}{x+5}=5 \\ \\ 5x+25=1-3x \\ 8x=-24 \\ x=-3\in(-5;\ \frac{1}{3})" alt="lg(1-3x)-lg(x+5)=lg5 \\ 1-3x>0 \\ x+5>0 \\ x\in(-5;\ \frac{1}{3}) \\ \\ \frac{1-3x}{x+5}=5 \\ \\ 5x+25=1-3x \\ 8x=-24 \\ x=-3\in(-5;\ \frac{1}{3})" align="absmiddle" class="latex-formula">
Ответ: -3