Ребятки,помогите решить ;)

$\frac{log_2(1+\frac{1}{x-1})}{log_2(x-1)*log_2x}+\frac{log_2(1+\frac{1}{x})}{log_2(x+1)*log_2x}=$

$=\frac{log_2\frac{x-1+1}{x-1}}{log_2(x-1)*log_2x}+\frac{log_2\frac{x+1}{x}}{log_2(x+1)*log_2x}=\frac{log_2\frac{x}{x-1}}{log_2(x-1)*log_2x}+\frac{log_2\frac{x+1}{x}}{log_2(x+1)*log_2x}$

$=\frac{log_2x-log_2(x-1)}{log_2(x-1)*log_2x}+\frac{log_2(x+1)-log_2x}{log_2(x+1)*log_2x}=$

$\frac{log_2(x+1)*log_2x-log_2(x+1)*log_2(x-1)+log_2(x-1)*log_2(x+1)-log_2(x-1)*log_2x}{log_2(x+1)*log_2(x-1)*log_2x}=$

$=\frac{log_2x(log_2(x+1)-log_2(x-1))}{log_2(x+1)*log_2(x-1)*log_2x}=\frac{log_2(x+1)-log_2(x-1)}{log_2(x+1)*log_2(x-1)}=$

$\frac{log_2\frac{x+1}{x-1}}{log_2(x+1)*log_2(x-1)}$

................................................................................................