Решите уравнение cosx + 2cos2x = 1
cosx + 2cos2x = 1
-2sin^2(x)+2cos^2(x)+cos(x)=1
n Е Z
2cos3x = 1
cos3x = 1/2
3x = +-arccos 1/2 + 2Пn
3x = +- П/3 + 2Пn
x = +- П/6 + 2Пn/3, n Є Z