Решите уравнение : А) x^2-2x-3=0 Б) x^2-6x+8=0
А) D = b^2 - 4ac = (-2)^2 - 4·1·(-3) = 4 + 12 = 16 x1 = 2 - 4/2 = -2/2 = -1 x2 = 2 + 4/2 = 6/2 = 3 Б) D = b^2 - 4ac = (-6)^2 - 4·1·+8 = 36 - 32 = 4 x1 = 6 - 2/2 = 4/2 = 2 x2 = 6 + 2/2 = 8/2 = 4