Ctg3x=-√3 ctg 4x=1 sin 4x=-√3/2 Помогите

Question

Ctg3x=-√3
ctg 4x=1
sin 4x=-√3/2
Помогите

Answer 1

1) Ctg3x = -√3
3x = arcCtg(-√3) + πk , k ∈Z
3x = 5π/6 + πk, k ∈∈Z
x = 5π/18 + πk/3 , k ∈Z
2) Ctg 4x = 1
4x = π/4 + πk, k ∈Z
x = π/16 + πk/4 , k ∈Z
3) Sin4x = -√3/2
4x = (-1)^(n+1) π/3 + nπ, n ∈Z
x = (-1)^(n+1) π/12+ nπ/4 , n ∈∈Z