(a^4-b^4)^3-(a^6-b^6)2+3a^4b^4(a^4-b^4)-2b^12

Question

(a^4-b^4)^3-(a^6-b^6)2+3a^4b^4(a^4-b^4)-2b^12

Answer 1

(а⁴-б⁴)-(а^6-б^6)+3а⁴б⁴(а⁴-б⁴)-2б¹²= а¹²-б¹²-а¹²+б¹²+3а^16б⁴-3а⁴б^16-2б¹²= 3а^16б⁴-3а⁴б^16-2б¹²