(2b+3)³=(2b)³+(2b)²3+2b3²+3³=8b³+12b²+18b+27
(3c-1)³=(3c)³-(3c)²1+3c1²-1³= 27c³-9c²+3c-1
(2a+3b)³=(2a)³+(2a)²3b+2a(3b)²+(3b)³=8a³+12a²b+18b²+27b³
(3a-2b)³=(3a)³-(3a)²2b+3a(2b)²-(2b)³=27a³-18a²b+12ab²-8b³
(-a-b)³=(-a)³-(-a)²b+(-a)b²-b³=-a³-a²b-ab²-b³
(2a+b)²=8a³+(2a)²b+2ab²+b³