1
Разделим 1 уравнение на 2
(2^x*3^y)/(2^y*3^x)=24/54
2^(x-y)/3^(x-y)=4/9
(2/3)^(x-y)=(2/3)²
x-y=2⇒x=y+2
4*2^y*3^y=24
6^y=6
y=1
x=3
(3;1)
2
3^(2x+y)=81⇒2x+y=4⇒y=4-2x
(x+y)²=9x
(4-2x+x)²=9x
(4-x)²=9x
16-8x+x²-9x=0
x²-17x+16=0
x1+x2=17 U x1*x2=16
x1=1⇒y1=2
x2=16⇒y2=-28
(1;2);(16;-28)