Помогите решить пожалуйста!!!

Решите задачу:

$\frac{(2^X-2^(2-x) - 3)}{2^x-2} \geq 0,2^x = t, \frac{t- \frac{4}{t}-3 }{t-2} \geq 0, \left \{ {{t- \frac{4}{t}-3 \geq 0} \atop {t-2\ \textgreater \ 0}} \right.,t \neq 0, \left \{ {{t\ \textgreater \ 2} \atop {t^2-3t-4 \geq 0}} \right.$ $t\ \textgreater \ 4. \left \{ {{t- \frac{4}{t}-3 \ \textless \ 0} \atop {t\ \textless \ 2}} \right., \left \{ {{t\ \textgreater \ -1} \atop {t\ \textless \ 2}} ,x\ \textless \ 1,x\ \textgreater \ 2\right.$