Решение
1) y` = 5x³ - 6x² + 1
y = C₁ + (5x⁴)/4 - (6x³/3) + x
y = C₁ + (5/4)*x⁴ - 2x³ + x
y(-1) = 1
1 = C₁ + (5/4)*(-1)⁴ - 2*(-1)³ + (-1)
C₁ = 1 - 1,25 - 2 + 1 = - 1,25
C₁ = -1,25
y = - 1,25 + (1,25)*x⁴ - 2x³ + x
2) y`` = 5 - 4x
y` = C₁ + 5x - 4*(x²/2) = C₁ + 5x - 2x²
y = C₂ + C₁ *X + 5*(X²/2) + 2*(X³/3)
Y = C₂ + C₁ *X + 2,5*X² + (2/3)*X³