N261 50 балов дам по фасту Го Го Го

Question

N261 50 балов дам по фасту Го Го Го

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Answer 1

1
-(a-2)/(a+1)(a²-a+1)-(1-a)/(a²-a+1)=(-a+2-a+a²-1+a)/(a+1)(a²-a+1)=
=(a²-a+1)/(a+1)(a²-a+1)=1/(a+1)
2
(2m-20)/(m-2)(m+2)+4/(m-2)-6/m=(2m²-20m+4m+8-6m²+24)/m(m²-4)=
=(-4m²-16m+32)/m(m²-4)=-4(m²+4m-8)/m(m²-4)
3
(2m²-n²)/(m+n)(m²-mn+n²)-(m-n)/(m²-mn+n²)=
=(2m²+n²-m²+n²)/(m³+n³)=(m²+2n²)/(m³+n³)
4
1/(x+3)-(x²+18)/(x+3)(x²-3x+9)=(x²-3x+9-x²-18)/(x+3)(x²-3x+9)=
=(-3x-9)/(x+3)(x²-3x+9)=-3(x+3)/(x+3)(x²-3x+9)=-3/(x²-3x+9)

Answer 2

1. -(a-2)/(a+1)(a^2-a+1))-(1-a)/(a^2-a+1)= -(a-2)-(1-a)(a+1))/(a+1)(a^2-a+1)= -(a-2)-(a+1-a^2-a))/(a+1)(a^2-a+1)=(a^2-a+1)/(a+1)(a^2-a+1)=
1/(a+1)
2. ((2(m-10)/(m-2)(m+2))+4/(m-2)-6/m=
=(2m(m-10)+4m(m+2)-6(m^2-4))/(m(m-2)(m+2)= (-12m+24)/(m(m-2)(m+2)= -12/(m(m+2)
3. (2m^2-n^2)/(m+n)(m^2-mn+n^2))-(m-n)/(m^2-mn+n^2)=
(2m2-n^2-m^2+n^2)/(m^3+n^3)=m^2/(m^3+n^3)
4. (1/(x+3))-(x^2+18)/(x+3)(x^2-3x+9)=(x^2-3x+9-x^2-18)/(x+3)(x^2-3x+9)= (-3(x+3))/(x+3)(x^2-3x+9)= -3/(x-3)^2